Bandidas

This movie was horrible. Not Soul plane horrible or even My super ex-girlfriend horrible, but I had to pause for a second to come up with those two examples. Unbelievable that Salma Hayek actually appears with a straight face in a small special in the DVD explaining how Penélope Cruz and herself wanted for so long to collaborate, to make this movie together. How insulting! Avoid it like the plague.

One Response to Bandidas

Harsh J says:

March 17, 2007 at 10:49 pm

Yeah it did suck but then, people do anything to watch Salma’s.

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Mathoverflow

Answer by Andrés E. Caicedo for "Weakly" Woodin cardinals May 28, 2017

(As I pointed out in a comment) yes, partial Woodinness is common in arguments in inner model theory. Accordingly, you obtain determinacy results addressing specific pointclasses (typically, well beyond projective). To illustrate this, let me "randomly" highlight two examples: See here for $\Sigma^1_2$-Woodin cardinals and, more generally, the noti […]

Andrés E. Caicedo

Answer by Andrés E. Caicedo for Completion of ZFC November 22, 2010

I am not sure which statement you heard as the "Ultimate $L$ axiom," but I will assume it is the following version: There is a proper class of Woodin cardinals, and for all sentences $\varphi$ that hold in $V$, there is a universally Baire set $A\subseteq{\mathbb R}$ such that, letting $\theta=\Theta^{L(A,{\mathbb R})}$, we have that $HOD^{L(A,{\ma […]

Andrés E. Caicedo

Answer by Andrés E. Caicedo for Is there a natural inner model of AD$_\mathbb{R}$? May 13, 2017

A Wadge initial segment (of $\mathcal P(\mathbb R)$) is a subset $\Gamma$ of $\mathcal P(\mathbb R)$ such that whenever $A\in\Gamma$ and $B\le_W A$, where $\le_W$ denotes Wadge reducibility, then $B\in\Gamma$. Note that if $\Gamma\subseteq\mathcal P(\mathbb R)$ and $L(\Gamma,\mathbb R)\models \Gamma=\mathcal P(\mathbb R)$, then $\Gamma$ is a Wadge initial se […]

Andrés E. Caicedo

Answer by Andrés E. Caicedo for Which types of Diophantine equations are solvable? January 13, 2011

Craig: For a while, there was some research on improving bounds on the number of variables or degree of unsolvable Diophantine equations. Unfortunately, I never got around to cataloging the known results in any systematic way, so all I can offer is some pointers to relevant references, but I am not sure of what the current records are. Perhaps the first pape […]

Andrés E. Caicedo

Answer by Andrés E. Caicedo for Is there a Darboux function like the one described below? April 12, 2017

Yes. Consider, for instance, Conway's base 13 function $c$, or any function that is everywhere discontinuous and has range $\mathbb R$ in every interval. Pick continuous bijections $f_n:\mathbb R\to(-1/n,1/n)$ for $n\in\mathbb N^+$. Pick a strictly decreasing sequence $(x_n)_{n\ge1}$ converging to $0$. Define $f$ by setting $f(x)=0$ if $x=0$ or $\pm x_n […]

Andrés E. Caicedo

Math.StackExchange

Answer by Andrés E. Caicedo for Is it possible to formalize the idea that large cardinal axioms don't limit us, while their negations do? November 25, 2013

One way we formalize this "limitation" idea is via interpretative power. John Steel describes this approach carefully in several places, so you may want to read what he says, in particular at Solomon Feferman, Harvey M. Friedman, Penelope Maddy, and John R. Steel. Does mathematics need new axioms?, The Bulletin of Symbolic Logic, 6 (4), (2000), 401 […]

Andrés E. Caicedo

Answer by Andrés E. Caicedo for Is there an algebraic homomorphism between two Banach algebras which is not continuous? November 23, 2010

"There are" examples of discontinuous homomorphisms between Banach algebras. However, the quotes are there because the question is independent of the usual axioms of set theory. I quote from the introduction to W. Hugh Woodin, "A discontinuous homomorphism from $C(X)$ without CH", J. London Math. Soc. (2) 48 (1993), no. 2, 299-315, MR1231 […]

Andrés E. Caicedo

Answer by Andrés E. Caicedo for $(\kappa^+)^\alpha=\kappa^\alpha\cdot \kappa^+$ May 29, 2017

This is Hausdorff's formula. Recall that $\tau^\lambda$ is the cardinality of the set ${}^\lambda\tau$ of functions $f\!:\lambda\to\tau$, and that $\kappa^+$ is regular for all $\kappa$. Now, there are two possibilities: If $\alpha\ge\tau$, then $2^\alpha\le\tau^\alpha\le(2^\alpha)^\alpha=2^\alpha$, so $\tau^\alpha=2^\alpha$. In particular, if $\alpha\g […]

Andrés E. Caicedo

Answer by Andrés E. Caicedo for Definition of nonstandard $\omega$ May 27, 2017

Fix a model $M$ of a theory for which it makes sense to talk about $\omega$ ($M$ does not need to be a model of set theory, it could even be simply an ordered set with a minimum in which every element has an immediate successor and every element other than the minimum has an immediate predecessor; in this case we could identify $\omega^M$ with $M$ itself). W […]

Andrés E. Caicedo

Answer by Andrés E. Caicedo for Axiom of binary choice vs Axiom of finite choice May 23, 2017

The study of finite choice axioms is quite interesting. Besides the reference given in Asaf's answer, there are a few papers covering this topic in detail. If you can track it down, I suggest you read MR0360275 (50 #12725) Reviewed. Conway, J. H. Effective implications between the "finite'' choice axioms. In Cambridge Summer School in Mat […]

Andrés E. Caicedo

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Bandidas

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