Recall that a function of two variables defined on an open domain
is harmonic iff
is
(i.e., all four second order derivatives
exist and are continuous in
), and
satisfies Laplace equation
As mentioned in problem 6 of the Fall 2008 Calculus III final exam, a function is a harmonic conjugate of
iff
is defined on
,
and
exist, and the Cauchy-Riemann equations hold:
and
.
It follows immediately from the Cauchy-Riemann equations that if is a harmonic conjugate of a harmonic function
, then
is also
, with
,
,
and
. It is also immediate that
satisfies Laplace equation because
, since continuity guarantees that the mixed partial derivatives commute. Thus
is also harmonic.
In fact, modulo continuity of the second order derivatives, the harmonic functions are precisely the functions that (locally) admit harmonic conjugates.
To see this, assume first that is
in
and that it admits a harmonic conjugate
. Then
and
so
and
was harmonic to begin with.
Conversely, assume that is harmonic in
. Suppose first that
is (connected and) simply connected. I claim that then
admits a harmonic conjugate
in
. To see this, letting
, notice that the existence of
is equivalent to the claim that
is a gradient vector field, since
iff
is a harmonic conjugate of
But, since
is simply connected, then
is a gradient iff it is conservative, i.e.,
for any simple piecewise smooth loop
in
. Fix such a
, and let
denote its interior. Then, by Green’s theorem,
where the sign is to be chosen depending on the orientation of
. It follows that
is indeed conservative and therefore a gradient, so
admits a harmonic conjugate.
Finally, if is not simply connected, we cannot guarantee that such a
exists in all of
, but the argument above shows that it does in any open (connected) simply connected subset of
, for example, any open ball contained in
. That we cannot extend this to all of
follows from considering, for example,
in
. This is a harmonic function but it does not admit a harmonic conjugate in
, since there is no continuous
in
. This example can be easily adapted (via a translation) to any non-simply connected
.
I close by remarking that, as mentioned in my previous post on average values of harmonic functions, one can use Green’s theorem to prove that harmonic functions satisfy the average (or mean) value property, and this property characterizes harmonicity as well, implies that
is actually
(i.e.,
admits partial derivatives of all orders, and they are all continuous) and has the additional advantage that it only requires that
is continuous, rather than
. Similarly, one can show that the Cauchy-Riemann equations on
suffice to guarantee that
and
are harmonic (and in particular,
). However, one needs to require that the equations hold everywhere on
. A pointwise requirement would not suffice. But I won’t address this issue here (I mention it in the notes in complex analysis that I hope to post some day).