2. Silver’s theorem.
From the results of the previous lectures, we know that any power can be computed from the cofinality and gimel functions (see the Remark at the end of lecture II.2). What we can say about the numbers
varies greatly depending on whether
is regular or not. If
is regular, then
As mentioned on lecture II.2, forcing provides us with a great deal of freedom to manipulate the exponential function
at least for
regular. In fact, the following holds:
Theorem 1. (Easton). If holds, then for any definable function
from the class of infinite cardinals to itself such that:
whenever
and
for all
there is a class forcing that preserves cofinalities and such that in the extension by
it holds that
for all regular cardinals
here,
is the function
as computed prior to the forcing extension.
For example, it is consistent that for all regular cardinals
(as mentioned last lecture, the same result is consistent for all cardinals, as shown by Foreman and Woodin, although their argument is significantly more elaborate that Easton’s). There is almost no limit to the combinations that the theorem allows: We could have
whenever
is regular and
is an even ordinal, and
whenever
for some odd ordinal
Or, if there is a proper class of weakly inaccessible cardinals (regular cardinals
such that
) then we could have
the third weakly inaccessible strictly larger than
for all regular cardinals
etc.
Morally, Easton’s theorem says that there is nothing else to say about the gimel function on regular cardinals, and all that is left to be explored is the behavior of for singular
In this section we begin this exploration. However, it is perhaps sobering to point out that there are several weaknesses in Easton’s result.
First, there is the assumption of in the ground model. When I began typing these notes, I was tempted to say that this is not a horribly serious problem, but then I actually thought about it. What I mean is this:
Question 2. Assume that is as above and also satisfies
3. for all regular cardinals
Does it follow that there is some cofinality-preserving forcing extension where for all regular cardinals
?
Years ago, Foreman, Magidor and Shelah asked whether the following is consistent: “Every nontrivial (set) forcing either adds a real or collapses a cardinal.”
This “maximality principle,” as they called it, implies that fails everywhere and there are no inaccessible cardinals (regular strong limit cardinals). Assuming that the principle is consistent gives us that nothing like Easton’s original approach would work to produce the cofinality preserving extensions we require. This is because Easton’s forcing is a product of class many nontrivial set forcings as factors. Of course, mutual genericity gives us that only set many of these factors can add reals, so at least one cardinal (probably a proper class) will be collapsed. This does not rule out that a completely different approach will give Easton’s result, but it makes the problem potentially more difficult than I originally imagined.
The work of Foreman, Magidor and Shelah on this “maximality principle” led to their discovery of Martin’s Maximum, arguably one of the most important events in modern set theory. A local version of the principle already follows from
, the bounded proper forcing axiom:
Theorem 3. (Todorčević). implies that every forcing that adds a subset of
must either add a real or collapse
For the proof, see Stevo Todorčević, Some combinatorial properties of trees, Bull. London Math. Soc., 14 (3),(1982), 213–217. All that is needed is that and that every tree
of height and size
is sealed, i.e., there is a function
such that whenever
and
then in fact
or
This notion is due to Baumgartner, who called these trees special. That these statements are consequences of
follows from work of Baumgartner and of Justin Moore. Todorčević requires that the forcing notion is a set, but one can dispense with this assumption.
An examination of the proof of Todorčević’s theorem actually shows that it answers Question 1 negatively. Very briefly, the argument is this: Assume and suppose that a forcing adds a subset of
but no reals. Given a name for this set, we can then build a tree of height
essentially the tree of attempts to decide the name. The assumption of
gives that the tree has size at most
and from it a cofinal map from
to
can be constructed.
Assume that is a forcing answering Question 1 affirmatively, where the function
satisfies
and
We then have
many distinct names for subsets of
to which the above procedure can be applied. It follows that the tree construction must fail, which only happens because some proper initial segment of the new subset is not in the ground model, so a new real is added. A mutual genericity argument ensures that there must be
many new reals added this way.
Second, Easton’s forcing preserves cofinalities and therefore cardinals. However, it does not preserve in general any significant large cardinals. For example, as we will see in Section 4, if is a measurable cardinal, then
is not the first counterexample to
so although Easton forcing preserves the fact that
is weakly inaccessible, it may very easily destroy its measurability. I do not know of any general Easton-like result for definable maps
that takes into account a significant amount of the large cardinal structure of the universe.
Third, of course, Easton’s result only applies to the regular cardinals. In fact, in the models obtained by Easton’s method we have no freedom whatsoever to manipulate the gimel function for singular cardinals. This can be made precise as follows:
Definition 4. The singular cardinals hypothesis, is the statement that for all cardinals
we have that
Note that the equality holds if is regular, so
only has content for singular cardinals, which explains its name. For such
notice that the left hand side is always at least as large as the right hand side, so what
says is that
is as small as possible for
singular.
is a trivial consequence of
and it is easy to see that it holds in the models obtained by Easton’s method. One may then wonder whether it is actually provable. Magidor showed that this is not the case; for example, beginning with significantly large cardinals, Magidor obtained a model in which
is a strong limit cardinal,
and
In this model fails since
There are simpler models of the failure of
I mentioned this one because it also witnesses a failure of Tarski’s conjecture, stated last lecture, the claim that
whenever
is a limit ordinal and
is a strictly increasing sequence of cardinals cofinal in
In effect, Tarski’s conjecture fails in Magidor model for as witnessed by the sequence
This is because
where the last equality follows from Tarski’s formula, Homework problem 8 (or from Theorem 10 in lecture II.2).
Magidor’s counterexample occurs at a singular cardinal of cofinality Silver’s remarkable result is that this must always be the case:
Theorem 5. (Silver). If holds for all singular cardinals of countable cofinality, then it holds everywhere.
Next time we will state Silver’s theorem in full generality and prove a particular case that illustrates the combinatorial ideas that guided the proof of the general result and its many generalizations. It follows from Silver’s theorem that in an Easton-like result that also considers singular cardinals the function must satisfy additional restrictions. I do not know of any general results of this kind, although many particular examples of possible behaviors and a significant list of restrictions have been identified.
A key feature of Silver’s result is the use of the notion of stationarity. In a sense, stationary sets are the first nontrivial manifestation of the axiom of choice at the uncountable level. Their definition requires an additional, very important notion.
Definition 6. Let be an ordinal. A set
is club in
if and only if it is closed in the order topology of
and it is cofinal in
(Club stands for “closed and unbounded.”)
The definition above is unnecessarily general. The empty set is club in A closed subset
of
is club if and only if
If
has cofinality
then, for any strictly increasing and cofinal function
its range is club in
and if
is closed in
then
is club if and only if
contains the range of such an
This means that the concept is not interesting if is a successor. Automatically, any intersection of clubs is club. It also means that the concept is not interesting if
has cofinality
as we can have disjoint club sets.
We want club sets to capture enough of the structure of that they can be used as surrogates for
A good working intuition is that club sets provide a measure of “size” of subsets of
A set is large if it contains a club. In order for this to be a reasonable notion of largeness, we need that no two large sets be disjoint. On the other hand, we don’t want that an arbitrary intersection of large sets be large.
This means that the notion of club set is only interesting (or at least, only captures our working intuition) for a limit ordinal of uncountable cofinality (as the following theorem verifies), and from now on when we mention a club subset of
we (perhaps implicitly) assume that
satisfies these non-triviality requirements.
It may be worth pointing out that the topological closure condition of a club set can be easily restated as follows: A set is closed in
iff for all
if
and
is unbounded in
then
Examples of club subsets of include the set of all countable limit ordinals, the set of all countable indecomposable ordinals of the form
for
limit (ordinal exponentiation), and many other, much more elaborate, sets. At first sight, it may look like these sets are actually rather thin, compared with, for example, the set of all countable successor ordinals. However, the closure condition in fact gives us that a club set has many “accumulation” points, and it is this reason what makes them so useful (and large, in some intuitive sense).
It is easy to verify that if is club in
then
the set of limit points of
(in the topological sense, as a subset of
) is also a club set, and we can iterate this procedure. In fact, we can iterate it for a long while:
Theorem 7. Assume that Then for any
the intersection of any
many club subsets of
is club.
Proof. Let be a sequence of club subsets of
where
Let
so
is closed, and all we need to verify is that it is unbounded.
For this, let be given. By induction on
we define a strictly increasing sequence
so that
for all
Assume that
has been defined, and
Since
the supremum
of this sequence is strictly below
Let
be least such that
Such an ordinal
exists since
is unbounded in
Let Again,
Repeat the above construction with
in place of
to obtain a sequence
Iterate this procedure
times. The sequences we have produced then satisfy that
is actually independent of
Call this ordinal
Since, by construction,
for all
it follows that
because
is closed in
(and
since
).
We have shown that and, by construction,
This shows that
is unbounded.
When is a regular cardinal, we can say even more.
Definition 8. Let be a regular cardinal and let
be a sequence of club subsets of
The diagonal intersection of the
in symbols,
is the set of all
such that
for all
For example, let Then
while if
then
is the set of limit ordinals below
What we are doing is “fattening up” the club sets
a tiny bit before taking their intersection: Given
let
for all
Then
Lemma 9. If is regular, the diagonal intersection of any
many club subsets of
is club in
This is as strong a result as we can hope for. Considering again the example of it is clear that we cannot strengthen the result to conclude that the intersection of
many club subsets of
is club in
Continuing in this fashion we build a strictly increasing -sequence
of elements of
and a sequence of club sets
such that
for all
Let
so
is club in
and let
so
Note that, for any
the ordinals
all belong to
so
Therefore,
If then
for some
, so
all belong to
and so does
It follows that
Since
we have that
is unbounded, as we wanted to show.
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