305 -Fields (4)

Suppose that {\mathbb F} is a field and that S\subset{\mathbb F}. It may be that S is also a field, using the same operations of {\mathbb F}. For example, if {\mathbb F}={\mathbb R}, then we could have S={\mathbb Q}.

Definition 15. If {\mathbb F} is a field and S\subset{\mathbb F}, we say that S is a subfield of {\mathbb F} if S is a field with the operations of {\mathbb F}.


Let’s examine this definition in some detail. Part of what this is saying is that

  1. If a,b\in S, then also a+b\in S, i.e., S is closed under addition.
  2. If a,b\in S, then also a\times b\in S, i.e., S is closed under multiplication.

However, this is not enough. For example, {\mathbb N} is not a field but it is closed under the addition and multiplication operations of {\mathbb R}.  The problem with {\mathbb N} is that it does not have additive or multiplicative inverses of its elements.

Proposition 16. Suppose that {\mathbb F} is a field and that a,b\in{\mathbb F}.

  •  If a+b=a then a=0.
  • If a\ne0 and ab=a then b=1.

Proof. Add the additive inverse -a to both sides of the first equation, and multiply by the multiplicative inverse a^{-1} both sides of the second equation. {\sf QED}

The point of Proposition 16 is the following: Suppose that S is a subfield of {\mathbb F}. Write 0^{\mathbb F} for the 0-th element of {\mathbb F} and 0^S for the 0-th element of S. Then 0^S=0^{\mathbb F}, in particular, 0 must belong to S. Similarly, 1^S=1^{\mathbb F}, so 1 belongs to S, as long as S contains some element other than 0. But, of course, if S is to be a field, then it must have at least two elements, so one of them must be different from 0.

Proposition 17. Suppose {\mathbb F} is a field and that a,b\in{\mathbb F}.

  • If a+b=0 then b=-a.
  • If ab=1 then a\ne0 and b=a^{-1}. \Box

Proposition 17 can be proved by a very similar argument to that of Proposition 16, so I omit the proof. The point of this proposition is that if S is a subfield of {\mathbb F}, and a\in S then the additive inverse of a from the point of view of {\mathbb F} and its additive inverse from the point of view of S must coincide. Similarly, the multiplicative inverse from the point of view of S of any nonzero element of S is the same as its multiplicative inverse from the point of view of {\mathbb F}. Hence, to properties 1,2 listed above we can add:

3. If a\in S, then -a\in S.

And:

4. If a\in S, and a\ne0, then a^{-1}\in S.

It turns out that 1–4 characterize subfields:

Theorem 18. Suppose {\mathbb F} is a field and S\subseteq {\mathbb F}. If S satisfies 1–4 and has at least two elements, then S is a subfield of {\mathbb F}.

Notice that we cannot remove the assumption that S has two elements. For example, S={0} satisfies properties 1–4 but is not a field.

We will prove this theorem next lecture and use it to produce many new examples of fields.

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2 Responses to 305 -Fields (4)

  1. […] -Fields (5) At the end of last lecture we stated a theorem giving an easy characterization of subfields of a given field We begin by […]

  2. […] the end of last lecture we stated a theorem giving an easy characterization of subfields of a given field We begin by […]

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