These questions are due Friday, April 9 at the beginning of lecture.
- Let
be the function given by
Show that
is a bijection.
- Define
by setting
and, if
then, letting
be the smallest prime such that
then
[Here,
.] Compute
for
and show that
is one-to-one.
Here are some suggestions. This does not mean you have to follow them, but they may be useful.
One way of showing that
is one-to-one is to prove the following by induction on
: For any
if
and
then 
In problem 1, you need to show
is 1-1 and onto. To show onto: Prove by induction on
that the equation
has a solution
So, you have to find a solution to
and, from a solution to
you need to construct a solution
to 
I strongly suggest that you try a few values first, to get a good idea of what is going on. Once you have an idea, the following will make more sense:
to find
with
it is best to look at two cases, whether
or whether 
Given
To show 1-1: Suppose
You need to show
and
Begin by showing that
One way of doing this is to show that if
then 
From this, and the definition of
it should now be easy for you to show that if
then
And then, of course, it follows that 