HW 6 is due Thursday, April 16 and HW 7 is due Tuesday, April 21, both at the beginning of lecture.
HW6
Work in hyperbolic geometry.
1. Let
and
be two parallel lines admitting a common perpendicular: There are points
and
with
perpendicular to both
and
. Suppose that
are other points in
with
, that is,
is between
and
. Let
be the foot of the perpendicular from
to
, and let
be the foot of the perpendicular from
to
.
Show that
. That is,
and
drift apart away from their common perpendicular.
(Note that
and
are Lambert quadrilaterals, and therefore
and
. The problem is to show that
.)
As an extra credit problem, show that for any number
we can find
(on either side of
) such that
, that is,
and
not just drift apart but they do so unboundedly.
2. Now suppose instead that
and
are critical (or limiting) parallel lines, that is, they are parallel, and if
and
is the foot of the perpendicular from
to
, then on one of the two sides determined by the line
, any line through
that forms with
a smaller angle than
does, cuts
at some point.
On the same side as just described, suppose that
are points on
with
, that is,
is between
and
. Let
be the foot of the perpendicular from
to
, and let
be the foot of the perpendicular from
to
.
Show that
. That is,
and
approach each other in the appropriate direction.
As an extra credit problem, show that for any
we can choose
so that
. That is,
and
are asymptotically close to one another. Do they drift away unboundedly in the other direction?
HW 7
Show that the critical function
is continuous. Recall that
measures the critical angle, that is,
iff there are critical parallel lines
and
and a point
such that if
is the foot of the perpendicular from
to
, and
, then
and
make an angle of measure
in the appropriate direction.
(In lecture we verified that
is strictly decreasing. This means that the only possible discontinuities of
are jump discontinuities. We also verified that
approaches
as
, and approaches
as
. It follows that to show that
has no jump discontinuities, it suffices to verify that it takes all values between
and
, that is, one needs to prove that for any
there is an
such that
.)