HW 8 is due Tuesday, April 28, at the beginning of lecture.
Work in hyperbolic geometry. Given a triangle , recall that its Saccheri quadrilateral
based at
is defined as follows: Let
be the midpoint of
and
be the midpoint of
. Let
be the feet of the perpendiculars from
and
to
respectively.
Continuing with the same notation, suppose now that is an arbitrary point on
, and let
be a point on the ray
with
. Show that
is also the Saccheri quadrilateral of
based at
.