HW 8 is due Tuesday, April 28, at the beginning of lecture.
Work in hyperbolic geometry. Given a triangle , recall that its Saccheri quadrilateral based at is defined as follows: Let be the midpoint of and be the midpoint of . Let be the feet of the perpendiculars from and to respectively.
Continuing with the same notation, suppose now that is an arbitrary point on , and let be a point on the ray with . Show that is also the Saccheri quadrilateral of based at .