Help us identify all mathematicians in this picture (click on it for a larger version). Please post comments here, on G+, or email me or Paul Larson.

The picture will appear in the book of proceedings of the Woodin conference, http://logic.harvard.edu/woodin_meeting.html. (Thanks to David Schrittesser for allowing us to use it.)

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Douglas Blue
Scott Cramer
Liuzhen Wu
Nam Trang
Daisuke Ikegami
Xianghui Shi
Vincenzo Dimonte
Joseph Van Name
Tony Martin
Alexander Kechris
Joan Bagaria
Laura Fontanella
Paul McKenney
Kaethe Minden
Kameryn Williams
Paul Larson
Sheila Miller
Ronald Jensen
Steve Homer
Juliette Kennedy
David Schrittesser
W Hugh Woodin
Gunter Fuchs
Arthur Apter
Menachem Magidor
Charles Parsons
Jouko Väänänen
Ralf Schindler
Rehana Patel
Nate Ackerman
John Steel
George Kafkoulis
Ilijas Farah
Martin Zeman
Assaf Peretz
Grigor Sargsyan
Akihiro Kanamori
Trevor Wilson
Maryanthe Malliaris
Hossein Lamei Ramandi
Philip Welch
H Garth Dales
Derrick DuBose
Gabriel Goldberg
Joel David Hamkins
Ted Slaman
Jacob Davis
Doug Hoffman
Joshua Reagan
Matthew Foreman
Zeynep Soysal
Daniel Rodríguez
Peter Koellner

(On behalf of all the editors of the volume, thanks to Benedikt Löwe, Iian Smythe, Miha Habič, Joel David Hamkins, Asaf Karagila, Yizheng Zhu, and Derrick DuBose.)

Here are a few more:
– Nate Ackerman’s face is visible next to Ralf Schindler.
– Maryanthe Malliaris is between Grigor and me.
– Kaethe Minden is in front between Martin and Woodin.
– Jacob Davis is in front in red coat.
– Joseph van Name is in red shirt in front of Joan Bagaria.

Matt Foreman to the right of Derrick DuBose, Hossein Lamei Ramandi (I think) to the left behind Philip Welch, George Kafkoulis (I think) behind Ilijas Farah, Paul McKenney in green windbreaker at back behind Laure Fontanella,

The technique of almost disjoint forcing was introduced in MR0289291 (44 #6482). Jensen, R. B.; Solovay, R. M. Some applications of almost disjoint sets. In Mathematical Logic and Foundations of Set Theory (Proc. Internat. Colloq., Jerusalem, 1968), pp. 84–104, North-Holland, Amsterdam, 1970. Fix an almost disjoint family $X=(x_\alpha:\alpha

At the moment most of those decisions come from me, at least for computer science papers (those with a 68 class as primary). The practice of having proceedings and final versions of papers is not exclusive to computer science, but this is where it is most common. I've found more often than not that the journal version is significantly different from the […]

The answer is no in general. For instance, by what is essentially an argument of Sierpiński, if $(X,\Sigma,\nu)$ is a $\sigma$-finite continuous measure space, then no non-null subset of $X$ admits a $\nu\times\nu$-measurable well-ordering. The proof is almost verbatim the one here. It is consistent (assuming large cardinals) that there is an extension of Le […]

I assume by $\aleph$ you mean $\mathfrak c$, the cardinality of the continuum. You can build $D$ by transfinite recursion: Well-order the continuum in type $\mathfrak c$. At stage $\alpha$ you add a point of $A_\alpha$ to your set, and one to its complement. You can always do this because at each stage fewer than $\mathfrak c$ many points have been selected. […]

Stefan, "low" cardinalities do not change by passing from $L({\mathbb R})$ to $L({\mathbb R})[{\mathcal U}]$, so the answer to the second question is negative. More precisely: Assume determinacy in $L({\mathbb R})$. Then $2^\omega/E_0$ is a successor cardinal to ${\mathfrak c}$ (This doesn't matter, all we need is that it is strictly larger. T […]

The power of a set is its cardinality. (As opposed to its power set, which is something else.) As you noticed in the comments, Kurepa trees are supposed to have countable levels, although just saying that a tree has size and height $\omega_1$ is not enough to conclude this, so the definition you quoted is incomplete as stated. Usually the convention is that […]

The key problem in the absence of the axiom of replacement is that there may be well-ordered sets $S$ that are too large in the sense that they are longer than any ordinal. In that case, the collection of ordinals isomorphic to an initial segment of $S$ would be the class of all ordinals, which is not a set. For example, with $\omega$ denoting as usual the f […]

R. Solovay proved that the provably $\mathbf\Delta^1_2$ sets are Lebesgue measurable (and have the property of Baire). A set $A$ is provably $\mathbf\Delta^1_2$ iff there is a real $a$, a $\Sigma^1_2$ formula $\phi(x,y)$ and a $\Pi^1_2$ formula $\psi(x,y)$ such that $A=\{t\mid \phi(t,a)\}=\{t\mid\psi(t,a)\}$, and $\mathsf{ZFC}$ proves that $\phi$ and $\psi$ […]

Yes, the suggested rearrangement converges to 0. This is a particular case of a result of Martin Ohm: For $p$ and $q$ positive integers rearrange the sequence $$\left(\frac{(−1)^{n-1}} n\right)_{n\ge 1} $$ by taking the ﬁrst $p$ positive terms, then the ﬁrst $q$ negative terms, then the next $p$ positive terms, then the next $q$ negative terms, and so on. Th […]

Yes, by the incompleteness theorem. An easy argument is to enumerate the sentences in the language of arithmetic. Assign to each node $\sigma $ of the tree $2^{

There are 53 people in the picture.

Roughly from left to right,

Douglas Blue

Scott Cramer

Liuzhen Wu

Nam Trang

Daisuke Ikegami

Xianghui Shi

Vincenzo Dimonte

Joseph Van Name

Tony Martin

Alexander Kechris

Joan Bagaria

Laura Fontanella

Paul McKenney

Kaethe Minden

Kameryn Williams

Paul Larson

Sheila Miller

Ronald Jensen

Steve Homer

Juliette Kennedy

David Schrittesser

W Hugh Woodin

Gunter Fuchs

Arthur Apter

Menachem Magidor

Charles Parsons

Jouko Väänänen

Ralf Schindler

Rehana Patel

Nate Ackerman

John Steel

George Kafkoulis

Ilijas Farah

Martin Zeman

Assaf Peretz

Grigor Sargsyan

Akihiro Kanamori

Trevor Wilson

Maryanthe Malliaris

Hossein Lamei Ramandi

Philip Welch

H Garth Dales

Derrick DuBose

Gabriel Goldberg

Joel David Hamkins

Ted Slaman

Jacob Davis

Doug Hoffman

Joshua Reagan

Matthew Foreman

Zeynep Soysal

Daniel Rodríguez

Peter Koellner

(On behalf of all the editors of the volume, thanks to Benedikt Löwe, Iian Smythe, Miha Habič, Joel David Hamkins, Asaf Karagila, Yizheng Zhu, and Derrick DuBose.)

Some more:

– Douglas Blue (top left corner)

– Hossein Ramandi (back row, between Trevor Wilson and Phillip Welch)

– Matt Foreman (far right)

Thank you, Miha!

Here are a few more:

– Nate Ackerman’s face is visible next to Ralf Schindler.

– Maryanthe Malliaris is between Grigor and me.

– Kaethe Minden is in front between Martin and Woodin.

– Jacob Davis is in front in red coat.

– Joseph van Name is in red shirt in front of Joan Bagaria.

Behind Nate might be (partial forehead view only) Rehana Patel?

Matt Foreman to the right of Derrick DuBose, Hossein Lamei Ramandi (I think) to the left behind Philip Welch, George Kafkoulis (I think) behind Ilijas Farah, Paul McKenney in green windbreaker at back behind Laure Fontanella,

Thank you, James.

Sorry, it seems it should be Joseph Van Name, with a capital V. (And also I usually go by my full name.)

Thanks, Joel! We are almost done; I think that, barring mistakes and typos, there are only 4 spots pending.

Can you point out the locations of the missing names?

Joel, I added descriptions at the beginning of the list.

The man behind Nam and in front of Daisuke is Liuzhen Wu. Xianghui Shi is misspelled.

Thank you, Yizheng.

Are we sure the last two are not set theorists from the future, that traveled back in time to attend this meeting?

Success!