I want to mention here an important property of harmonic functions, the mean value property, and some of its consequences. I restrict myself to functions of two variables for clarity.
Many important properties of harmonic functions (and, by extension, of analytic functions) can be established solely in the basis of the mean value property. I don’t know how to prove this property (or that it characterizes harmonicity) without appealing to Stokes’s theorem, or one of its immediate consequences (the topic of Chapter 14 of the book); in fact, I doubt such an approach is possible. It is a good exercise to see, at least formally, how this result gives the mean value property, but a rigorous treatment tends to be somewhat involved. Unfortunately, the arguments that show that the statements below hold tend to require techniques that are beyond the scope of Calculus III, so I will skip them.
1. Let be a harmonic function defined on an open region
of the plane, so
is twice continuously differentiable, and the equation
holds at all points in
.
Then satisfies the average (or mean) value property, namely, for any closed disk
contained in
,
where is the center of the disk
and
is of course the area of
,
, where
is the radius of
.
If one wants to explicitly compute double integrals over disks, like , it tends to be the case that introducing polar coordinates is rather helpful, if one parametrizes
appropriately. This usually means one represents an arbitrary point in
as
for some
and
, so
For example, let on
, so
is clearly harmonic since
. Consider the disk
of radius
centered at
. We have that
so
as claimed by the mean value property.
2. Conversely, if is a continuous function defined on an open region
and
satisfies the mean value property, i.e., for all closed disks
contained in
one has that
where is the center of
, then
is harmonic.
3. One of the first consequences one may notice of this fact is that it gives us that the function , originally only assumed to be continuous, is in fact twice continuously differentiable. Intuitively, one should expect this since
is expressed as a double integral of a continuous function. In fact, we can iterate this idea: Since
is twice continuously differentiable, then
can be expressed as a double integral of a twice continuously differentiable function, and so it is four times continuously differentiable, etc: Any harmonic function has continuous derivatives of all orders.
4. Another important consequence is that harmonic functions on (connected) open regions do not have any local maxima or minima, unless they are actually constant (in which case, of course, any point is a local maximum and a local minimum. This is because if is a local maximum or minimum of the harmonic function
, then the average value of
on any small disk around
is just
. If
is not constant on the disk, then for its average to be
, one must have points on the disk where the value of
is larger, and points where it is smaller. But then, since this holds no matter how small the disk one consider is, it follows that there are points arbitrarily close to
where
takes values larger than
, and also arbitrarily close points where
takes values smaller than
. But this means that after all,
is neither a local maximum nor a local minimum.
[Notice that if is harmonic, then
; why can’t we simply appeal to the second derivative test to conclude that all critical points of
must be saddle points?]
5. One can also show that if is constant on a small disk
then in fact it is constant through the whole region
(or at least, through the connected component of
containing
). Although the proof of this is not too difficult, I omit it since it requires a slightly subtler analysis of regions in the plane than we have covered in lecture.
[…] close by remarking that, as mentioned in my previous post on average values of harmonic functions, one can use Green’s theorem to prove that harmonic […]
[…] close by remarking that, as mentioned in my previous post on average values of harmonic functions, one can use Green’s theorem to prove that harmonic […]